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prophesilast Friday at 2:49 PM1 replyview on HN

The tl;dr is that breaking FHE would mean solving lattice problems that have been studied for decades to be nontrivial to break[0].

[0] https://arxiv.org/abs/2208.08125


Replies

JohnFenlast Friday at 2:54 PM

I'm not talking about the possibility of breaking FHE, though.

What I don't understand is this: if I get encrypted data from someone and, without breaking that encryption, I can perform computations on it that yield a sensible result (even if the result is also encrypted with a key I don't have), then how does that not mean the encryption has been weakened? If the encryption were strong, that should not be possible.

Actually breaking the encryption is a different thing, and I wasn't questioning that.

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