nooooo you don't understand. when the buffer is not full, the string will be zero terminated "in buffer" (which is how it works as is anyway). when the buffer is full, the "free count" at the end will do double duty, both as a zero count and a zero terminater
nooooo you don't understand. when the buffer is not full, the string will be zero terminated "in buffer" (which is how it works as is anyway). when the buffer is full, the "free count" at the end will do double duty, both as a zero count and a zero terminater