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eductionyesterday at 7:00 PM0 repliesview on HN

Oops last example should be $hash1->{“hash2”} - this is a whole hash referenced with $ because of the implementation detail that it is in hash1 as a reference, which is considered a scalar.

Technically you are allowed to use % like so: %{$hash1->{“hash2”}}. Which, just - lol.