> This gigantic dataset covers an area of the sky equivalent to 8600 full moons
What proportion of the celestial vault or sphere is that? Napkin calcul appreciated :)
The (average) full moon occupies roughly 1/129,600 of the sky, or 0.00077%
So this data set covers 6.6% of the night sky.
1 Full moon is about 0.5 degree if that helps
The (average) full moon occupies roughly 1/129,600 of the sky, or 0.00077%
So this data set covers 6.6% of the night sky.