This reminded me of one of my high school computer science assignments- simply to find all words in a single boggle board. And try to optimize your solution a bit. The point was to teach about recursion/backtracking and data structures. The intended solution was roughly: start at a square, check if your current prefix is a valid prefix, move to a neighbor recursively, and emit any words you find. Trying to optimize naturally motivates a trie data structure.

I found it to be at least an order of magnitude faster, though, to invert the solution: loop through each word in the dictionary and check whether it exists in the grid! The dictionary is small compared to the number of grid paths, and checking whether a word exists in the grid is very very fast, requiring not much backtracking, and lends itself well to heuristic filtering.