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JohnKemenytoday at 9:36 AM2 repliesview on HN

Is your argument that complex powers isn't anything?


Replies

xinu2020today at 9:51 AM

Their argument is that ln(z) where z is a complex number is a multi-valued function, so the statement "Explore why i^i is real number" could be misinterpreted as i^i = a single well-defined real value.

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ogogmadtoday at 5:07 PM

Do you know what a Riemann surface is? Because if you don't, then you don't know what you're talking about - and you should stop getting people confused.