You can do it even faster with the if statements:
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
if (argc < 2) {
fprintf(stderr, "Usage: %s <string>\n", argv[0]);
return 1;
}
char *s = argv[1];
int i;
/* find the end of the string */
for (i = 0; s[i] != '\0'; ++i)
;
/* make sure the string wasn't empty */
if (i == 0) {
fprintf(stderr, "Error: empty string\n");
return 1;
}
/* last character is at s[i - 1] */
char d = s[i - 1];
if (d == '0')
printf("even\n");
if (d == '1')
printf("odd\n");
if (d == '2')
printf("even\n");
if (d == '3')
printf("odd\n");
if (d == '4')
printf("even\n");
if (d == '5')
printf("odd\n");
if (d == '6')
printf("even\n");
if (d == '7')
printf("odd\n");
if (d == '8')
printf("even\n");
if (d == '9')
printf("odd\n");
return 0;
}
gcc -std=c11 -Wall -Wextra -O2 -o check_digit check_digit.c./check_digit 999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999
You inspired me this joyful rewrite:
#define _(e) { e;};
#define r(e) _(return e)
#define I(b, e) _(if (b) r(e));
#define W(e) _(while (1) _(e));
int main(int c, char **v) {
_(I(c != 2, -1) _(c = 0) W(I(!v[1][c++], v[1][c - 2] & 1)))
}probably easier in bash:
number="$1"
if [[ "$number" =~ "^(2|4|6|8|10|12|14|16|18|20)$" ]]; then
echo even
elif [[ "$number" =~ "^(1|3|5|7|9|11|13|15|17|19)$" ]]; then
echo odd
else
echo Nan
fi
A bit limited, but you can scale it up
You can do it even even faster by replacing your if statements (works because the ascii values end in the digit they represent):