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gpderetta • yesterday at 1:08 PM • 1 reply • view on HN

Same in C++. You can't do much with the function type itself as there are no objects with that type, but you can create references and pointers to it.

Replies

1718627440 • yesterday at 1:40 PM

But

    typedef void * (type) (void * args);

    type foo;

    a = foo (b);
works?
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