alt Hacker NewsThere are unspeakble types, such as lambdas, that are not exactly easy to handle without "auto". How a variable containing local lambda with captures will look without "auto"?
There are unspeakble types, such as lambdas, that are not exactly easy to handle without "auto". How a variable containing local lambda with captures will look without "auto"?
If it captures variables, it is not possible to manually declare the type. You can however hide it in an std::function. But then you probably get some overhead and some heap allocations in real life.