No. It can’t. It can only destroy its own reference to foo, not the calling scope’s reference.
Right, but I don't care about the reference to foo (that's a low-level detail that should be confined to systems languages, not application languages) I was asking about the foo.
alt Hacker News
Right, but I don't care about the reference to foo (that's a low-level detail that should be confined to systems languages, not application languages) I was asking about the foo.