alt Hacker NewsI don't see why?
The C committee gave you memset_explicit. But note that there is still no guarantee that information can not leak. This is generally a very hard problem as information can leak in many different ways as it may have been copied by the compiler. Fully memory safe languages (so "Safe Rust" but not necessarily real-word Rust) would offer a bit more protection by default, but then there are still side-channel issues.
Because, for the 1384th time, they're pretending they can ignore what the programmer explicitly told them to do
Creating memset_explicit won't fix existing code. "Oh but what if maybe" is just cope.
If I do memset then free then that's what I want to do
And the way things go I won't be surprised if they break memset_explicit for some other BS reason and then make you use memset_explicit_you_really_mean_it_this_time