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rahimiali01/15/20261 replyview on HN

just to be clear, semiseparate in this context means H = D + CC', where D is block diagonal and C is tall & skinny?

If so, it would be nice if this were the case, because you could then just use the Woodbury formula to invert H. But I don't think such a decomposition exists. I tried to exhaustively search through all the decompositions of H that involved one dummy variable (of which the above is a special case) and I couldn't find one. I ended up having to introduce two dummy variables instead.


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jeffjeffbear01/15/2026

> just to be clear, semiseparate in this context means H = D + CC', where D is block diagonal and C is tall & skinny?

Not quite, it means any submatrix taken from the upper(lower) part of the matrix has some low rank. Like a matrix is {3,4}-semiseperable if any sub matrix taken from the lower triangular part has at most rank 3 and any submatrix taken from the upper triangular part has at most rank 4.

The inverse of an upper bidiagonal matrix is {0,1}-semiseperable.

There are a lot of fast algorithms if you know a matrix is semiseperable.

edit: link https://people.cs.kuleuven.be/~raf.vandebril/homepage/public...

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