That's a possibility. Some code still assumes (without realizing!) x86 style ordered loads and stores. This is called a strong memory model, specifically TSO, Total Store Order. If you tell x86 to execute "a=1; b=2;", it will always store value to 'a' first. Of course compilers might reorder stores and loads, but that's another matter.

ARM is free to reorder stores and loads. This is called a weak memory model. So unless it's explicitly told to the compiler, like C++ memory_order::acquire and memory_order::release, you might get invalid behavior. Heisenbugs in the worst case.