> On the other hand, detecting integer overflow in software is extremely expensive
this just isn't true. both addition and multiplication can check for overflow in <2 instructions.
You are delusional.
Read the RISC-V documentation to see that you need at least 3 instructions.
For addition, overflow happens when you add 2 positive numbers and the result is negative, or when you add 2 negative numbers and the result is positive.
After using an instruction to do the addition, how can you detect this complex condition with a single instruction in the impoverished RISC-V ISA?
EDIT: Someone has downvoted this, presumably because I have not been polite enough.
That may be true, but I consider much more impolite the kind of misleading false information that has been written by the poster to whom I have replied. It is difficult to read that kind of b*s*t and be cool about it.
Fewer than two is exactly one instruction. Which?