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emih • today at 2:47 PM • 3 replies • view on HN

You can still do this though:

  let result = (barbalyze(c, d, $) . foobinade(a, b, $)) input
Or if you prefer left-to-right:

  let result = input
    |> foobinade(a, b, $)
    |> barbalyze(c, d, $)
Maybe what isn't clear is that this hole operator would bind to the innermost function call, not the whole statement.

Replies

twic • today at 3:08 PM

Even better, this method lets you pipeline into a parameter which isn't the last one:

  let result = input
    |> add_prefix_and_suffix("They said '", $, "'!")
➕ show 1 reply
Smaug123 • today at 5:12 PM

This is essentially how Mathematica does it: the sugar `Foo[x,#,z]&` is semantically the same as `Function[{y}, Foo[x,y,z]]`. The `&` syntax essentially controls what hole belongs where.

raincole • today at 2:59 PM

Wow, this convinced me. It's so obviously the right approach when you put it this way.