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coder68yesterday at 10:17 PM1 replyview on HN

It does? There is a fast drop followed by a long decay, exponential in fact. The cooling rate is proportional to the temperature difference, so the drop is sharpest at the very beginning when the object is hottest.


Replies

ameliusyesterday at 10:22 PM

I mean that initial drop doesn't look like it is part of the same exponential decay.