alt Hacker NewsShe determines that by having three copies. Or four. Or eight.
Tis just probabilities and unlikelihood of hitting a refresh cycle across that many memory channels all at once.
She determines that by having three copies. Or four. Or eight.
Tis just probabilities and unlikelihood of hitting a refresh cycle across that many memory channels all at once.
Right, but the impressive part is finding addresses that are actually on different memory channels.