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vlovich123yesterday at 3:16 AM1 replyview on HN

I want to count the number of possible permutations of the particles. We’ve now got a “larger” number than Ω will ever be able to represent by definition (even Ω² is minuscule by comparison).


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noviayesterday at 4:22 AM

yeah that seems fine. there's like no good reason to do that. are you trying to simulate reality or something?

but my point still stands, choose whichever calculation you think is important to be able to do with Ω, defined as f(Ω), square it for good measure, and set that as the max, the min, and the number of numbers in between each integer.

The total number of possible numbers will be ~2*f(Ω)⁴ which should be more than enough numbers :)

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