alt Hacker News10^-7 (loss/record) * 10^8 (record/year) yields 10 data losses per year. If you're even a medium sized business you need a much better than 10^-7 probability of losses.
10^-7 (loss/record) * 10^8 (record/year) yields 10 data losses per year. If you're even a medium sized business you need a much better than 10^-7 probability of losses.
That's only true if your typical loss event loses one record. If you have a one in a million chance of an array failure taking out 10% of your production database, and otherwise have zero possibility of data loss, you also get 10^-7 losses per record.
And I wouldn't assume they meant that number to be per record in the first place.