alt Hacker News> y'know you can check if an operator has been overloaded
And there lies the problem with C++: to be sure, you have to check. C++ code can't be taken at face value -- the most innocuous-looking code could be a ticking bomb.
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rfgplk • today at 4:58 PM
But isn't this a problem with all code? Looking at a Rust function signature how can you be sure that it does what it says it does? Or python?
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LoganDark • today at 4:53 PM
> C++ code can't be taken at face value -- the most innocuous-looking code could be a ticking bomb.
You can't take C code at face value either. The name of a method or type doesn't tell you what it does. It could longjmp for all you know.
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Just like any C function without looking into the translation unit, don't say you blindly believe on the function name.