logoalt Hacker News

js8yesterday at 6:41 AM2 repliesview on HN

I find it interesting that the counterexample uses C as a field. C is twisted and weird. Maybe the Jacobian Conjecture still holds for reals?


Replies

yorwbayesterday at 7:32 AM

All the coefficients and evaluation points are rational, so it's a counterexample in all fields where 2 ≠ 0 and 3 ≠ 0, doesn't matter whether that field is the complex numbers, real numbers, rational numbers or even a finite field.

show 1 reply
krackersyesterday at 6:43 AM

>C is twisted and weird.

Why do you say this? I've admittedly never done a proper complex analysis course but I got the impression that that complex differentiability was a very strong condition that results in holomprhic functions behaving "nicely" in ways that real functions do not

show 1 reply