> You do realize you sound exactly like a cult member right?
If you say so.
That doesn't change the fact that P(A|B) = P(B|A)P(A)/P(B).
There is nothing I could possibly say to convince you otherwise, in the same EXACT way I couldn't convince a scientologist that their thetan levels are nonsense. It was never the argument that conditional probability or other mathematics is wrong, nobody is ever arguing that, but that is all you disciples ever argue against. You are all deeply uneducated and unserious people believing to "reason" yourselves to some higher "truth" on all kinds of broad topics using some WILDLY misappropriated and misunderstood mathematical principles.
> That doesn't change the fact that P(A|B) = P(B|A)P(A)/P(B).
It didn't take long before a strawman got pulled out of nowhere. That's so typical, if one disagrees with the wild conjectures of the rationalists, which they call "axioms", they blame you for rejecting the Pythagorean Theorem or some such. Dishonesty is the defining feature of that "movement"