alt Hacker NewsIs it really a long running instruction? I mean, obviously yes, but what makes it slow is that it's doing an MMIO copy from a slow source. It's like a read(2) system call being "slow" because the fd is associated with a socket to the moon.
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kmeisthax • today at 7:44 PM
A read that happens to touch a particular torment nexus fd is still a long-running syscall, even if the syscall servicing routine itself is not long-running. The underlying problem is that program code that is "in a syscall" or "in an instruction" is in a special state for which interruption might not be possible or implemented well[0].
[0] Remember ITS and the PC2 problem?
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It's an instruction in the sense that timing boundaries are x86 instruction boundaries, which is what the security model bases itself on. So yeah, not an instruction in the strict CPU sense (microcode + micro-ops), but in the useful sense.