alt Hacker NewsChecking the following code, could you confirm that is does not work concurrently ? The "world" var is read-only, does it mean that all other entities are also readonly (cannot be modified by another thread, for instance) ?
struct World {
entities Vec<Entity>;
}
func step(world &World, entity in world.entities[] mut) {
entity.advance();
let collision = world.get_collision_for_entity(entity);
entity.resolve(collision);
}
Yep, that works today. The neat thing here is that `world` is immutable _except_ for its `.entities[]` elements.
That wouldn't be shareable with another thread, because part of it is `mut`. _Theoretically_ we could make this shareable with other threads if we had another kind of effect, let me know if you're curious about that.
The `entity in world.entities[] mut` gives `step` blanket permission to mutate any element inside world.entities. We wouldn't be able to say "all other entities are readonly".
Though, it's worth mentioning that `advance` and `resolve` both receive the entity as a unique reference (since it's the only reference into a group which has a mut effect).